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Physical Computing

assignment I

Selma Mataich

As for me, this assignment was quite tedious since I have no background in neither programming nor coding in general. A lot of missteps and long hours trying to understand multiple youtube videos, asking for help and trying to decipher the meaning of example solutions on the course page…I got there in the end!

But since I used a lot of different examples to understand the assignment I decided to try out a bit more things with the buttons and LEDs, which you can see below.

Documentation here

++Code of assignment 1:++

int led1 = 14;
int led2 = 15;
int btn = 16;
int btnState = 0;
int prevbtnState = 0;
int counter = 0; 


void setup()
{
pinMode(14, OUTPUT);
pinMode(15,OUTPUT);
pinMode (16, INPUT);
Serial.begin (9600);
}

void loop() 
{
        btnState = digitalRead(16);
 
if(btnState != prevbtnState) 
{if(btnState == HIGH) {
        counter++;
        if(counter>2){
         counter = 0;
        }
        Serial.println(counter);
}
}


prevbtnState = btnState;


switch  (btnState = counter)
 {
case 0: digitalWrite(14,LOW);
        digitalWrite(15,LOW);
        break;
case 1: digitalWrite(14,HIGH);
        digitalWrite(15,LOW);
        break;
case 2: digitalWrite(14,HIGH);
        digitalWrite(15,HIGH);
        break;


}


delay(10);
}

++Extra experiments:++

What if instead of two LED pins there are 4 and the light is turning on in different sequences?

int led1 = 14;
int led2 = 15;
int led3 = 13;
int led4 = 12;
int btn = 16;
int btnState = 0;
int prevbtnState = 0;
int counter = 0; 


void setup()
{
pinMode(12, OUTPUT);
pinMode(13,OUTPUT);
pinMode(14, OUTPUT);
pinMode(15,OUTPUT);
pinMode (16, INPUT);
Serial.begin (9600);
}

void loop() 
{
        btnState = digitalRead(16);
 
if(btnState != prevbtnState) 
{if(btnState == HIGH) {
        counter++;
        if(counter>8){
         counter = 0;
        }
        Serial.println(counter);
}
}


prevbtnState = btnState;


switch  (btnState = counter)
 {
case 0: digitalWrite(12,LOW);
        digitalWrite(13,LOW);
        digitalWrite(14,LOW);
        digitalWrite(15,LOW);
        break;
case 1: digitalWrite(12,HIGH);
        digitalWrite(13,LOW);
        digitalWrite(14,LOW);
        digitalWrite(15,LOW);
        break;
case 2: digitalWrite(12,HIGH);
        digitalWrite(13,HIGH);
        digitalWrite(14,LOW);
        digitalWrite(15,LOW);
        break;
case 3: digitalWrite(12,HIGH);
        digitalWrite(13,HIGH);
        digitalWrite(14,HIGH);
        digitalWrite(15,LOW);
        break;
case 4: digitalWrite(12,HIGH);
        digitalWrite(13,HIGH);
        digitalWrite(14,HIGH);
        digitalWrite(15,HIGH);
        break;
case 5: digitalWrite(12,LOW);
        digitalWrite(13,HIGH);
        digitalWrite(14,LOW);
        digitalWrite(15,HIGH);
        break;
case 6: digitalWrite(12,HIGH);
        digitalWrite(13,LOW);
        digitalWrite(14,HIGH);
        digitalWrite(15,LOW);
        break;    
case 7: digitalWrite(12,HIGH);
        digitalWrite(13,HIGH);
        digitalWrite(14,HIGH);
        digitalWrite(15,HIGH);
        break;  
case 8: digitalWrite(12,LOW);
        digitalWrite(13,LOW);
        digitalWrite(14,LOW);
        digitalWrite(15,LOW);
        break;     



}


delay(5);
}

What if this sequence happens without a button in a loop?

int led1 = 14;
int led2 = 15;
int led3 = 13;
int led4 = 12;
const int N = 4;  
int i = 0;


void setup() {
pinMode(12, OUTPUT);
pinMode(13,OUTPUT);
pinMode(14, OUTPUT);
pinMode(15,OUTPUT);
pinMode (16, INPUT);
Serial.begin (9600);



}
void loop() {
  
for (int i= 0; i < N; i++)

        digitalWrite(12,HIGH);
        delay(500);
        digitalWrite(13,HIGH);
        delay(500);
        digitalWrite(14,HIGH);
        delay(500);
        digitalWrite(15,HIGH);
        delay(500);
        digitalWrite(12,LOW);
        delay(500);
        digitalWrite(13,LOW);
        delay(500);
        digitalWrite(14,LOW);
        delay(500);
        digitalWrite(15,LOW);
        delay(500);
        
     
}